what proportion of a normal distribution falls between z=-.65 and z=+.65?
look up the probability to the left of z=.65, and subtract the probability to the left of z=-.65.
have you used a standard normal chart?
yes but its confusing its my first time and i dont know where to start
it is symmetric so you can also find 1-2* P(z<-.65)
ok let me find a chart online and ill help you
thank you so much
that's a good one, go there and let me know if the link works
the link wont work for some reason
ok let me see if I can find a similar one
that's only a partial table but you can get the basic idea
does it work?
yes it works so do i look up -,65 and .65
you would if it was a full table but we only have positive values here so we have to do some more work
you can start by looking up .65
the tenths place is in the first column, so go to .6
ok so i see .6
as you move over to the right you are adding one to the hundreths place. you can see the hundreths place an the top row of the chart
0.7422
look for .05, and find where the row .6 meets the column .05, that is the probability to the left of .65
yep that's right.
now we need to subtract P(z<-.65)
standard normal is symmetric so P(z<-.65)=P(z>.65)
so how would we find the negative
P(z>.65)=1-P(z<.65)=1-.7422=.2578
so P(z<.65)=.7422 P(z<-.65)=.2578 and we subtract them to find the probability in between .7422-.2578=.4844
if you had a full table you could have just looked up z=-.65
thanls so much, i really understand that now
great glad it helped :)
cya
bye:)
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