Question

find limit
lim as beta approaches 0 (sin Beta)/(9beta+tan Beta) Please show me step by steps

Answer 1

1/10

Answer 2

use the property that tanx/x and sinx/x is 1 wen x->0.

Answer 3

or you can use L'Hopitals rule since the form is 0/0 and take derivatives of top and bottom, then plug in beta=0

Answer 4

yes but i dont really understand if you show me step by step i would

Answer 5

do you know derivatives yet?

Answer 6

sin(b)/(9b+tanb)
pull out b from the denominator and so u get, sinb/b/(9+tanb/b)=>applying lim b->0 we get,
1/(9+1)=1/10

Answer 7

thnks