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evaluate the limit as x goes to 3: (5x^2-45)/(x^2-6x+9)
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\[\frac{5(x-3)(x+3)}{(x-3)(x-3)}\]
DNE
\[DNE\]
the numerator is 5(x+3)(x-3) the denominator is (x-3)^2 so now cancel out the common factors and evaluate.... as amistre tells it dne.
that's what I did! yay!
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