Question

5y^8-125 factor completely

Answer 1

i smell a diff of cube

Answer 2

= 5(y^8 - 25)
= 5[ (y^4)2 -5^2]

resolve further to get all the factors

Answer 3

it was disguised as a diff of squares tho... im suing my noseologist

Answer 4

5(y^8-25)=5(y^4+5)(y^2+sqrt(5))(y+\[5^{1/4}\])(y-\[5^{1/4}\])

Answer 5

5(y^8-25)
5(y^4-5)(y^4+5) by difference 2 squares

Answer 6

lol i have no idea where to even start , math is so not my thing

Answer 7

:D ur funny amistre :D

Answer 8

final ans

5(y^4+5)(y^2+root5)(y^2 - root5)

hope i hv resolved all properly....

Answer 9

Anyone??????

Answer 10

depend of what you want to factor it over. reals, integers, complex?

Answer 11

if you are factoring over integers you get
\[5(y^8-25)=5(y^4+5)(y^4+5)\]

Answer 12

typo
\[5(y^4+5)(y^4-5)\]

Answer 13

if reals you get
\[5(y^4+5)(y^2+\sqrt{5})(y^2-\sqrt{5})\]
\[=5(y^4+5)(y^2+\sqrt{5})(y+\sqrt[4]{5})(y-\sqrt[4]{5})\]

Answer 14

my guess is this was supposed to be factored over integers, so first answer is right.

Answer 15

if complex you get a whole nother can of worms