Question

A 45-45-90 triangle has a hypotenuse of length 7. What is the length of one of its legs? If necessary, round your answer to two decimal places.

Answer 1

7 more than normal

Answer 2

7/root2

Answer 3

i asked me math teacher today why they call it a normal; he doesnt know :)

Answer 4

Well: a^2+b^2=c^2. If the hypotenuse is 7 you have:
a^2+b^2=49 BUT its a 45-45-90. So the legs are the same so:
a^2+a^2=49
2a^2=49
a^2=49/2
a=7/sqrt(2)

Answer 5

sqrt(49/2)=4.95

Answer 6

lol amistre^^

Answer 7

\[7*\frac{\sqrt{2}}{2}\]

Answer 8

i gotta go to stats; have fun ;)

Answer 9

Oh yeah?!?!? \[7e^{i \frac{\pi}{4}}-7i \sin(\frac{\pi}{4})!!\].

Answer 10

now now... you keep up that notational language and your gonna poke out an "i"

Answer 11

O.x