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find the derivative of this function \[y=xe ^{-6x}\]
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using integration by parts, let u = x and dv = e^(-6x)
o whoops derivative
yes but how do i derivative the e^-6x
use the product rule
e^(-6x) + x(-6)e^(-6x)
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since the product rule says d/dx f(x)g(x) = f'(x)g(x) + g'(x)f(x) so let f(x) = x and g(x) = e^(-6x)
so thats the answer? e^(-6x)?
have look at the "solution.gif" above.
i did but i just dont understand....
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the derivative is right hand side of the equation.
"d/dx" means the derivative with respect to variable x.
i know but when i submit into my web assign it said its wrong...i dont understand how i did it myself too
i think result should be (e^(-6*x))*(1-6*x) * means multiplication.
ok..let me see
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