Question

Find the derivative dy/dx of
y=cos(e^x)

Answer 1

y' = -sin(e^x)*e^x

Answer 2

through chain rule:
f(g(x)) = f'(g(x)) * g'(x)

Answer 3

yes i got u=g(x) to be e^x and y=f(u) to cos(u)

Answer 4

but how do i derivative the function thats the only thing that kills me

Answer 5

Okay. You have u'f'(u). u'=e^x and f'=-sin(u).
So your derivative then is: e^x(-sin(e^x))

Answer 6

you need to identify functions that are within functions and then using the chain rule you work from the outside in

Answer 7

since e^x is a function and cos x is a function that are being used and you work from the outside in, you take the derivative of the outside function but leave the inside function the same and then you multiply it by the derivative of the inside function and repeat until you get to the derivative of x which is 1 and any number multiplied by itself is 1

Answer 8

i mean any number multiplied by itself is itself*

Answer 9

by 1,, bleh

Answer 10

"any number multiplied by one is itself***" xP

Answer 11

ok im save this so that i remember