How do you solve this problem? 8/3x^3-5/12x

Question

owlfred · Answer

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

amistre64 · Answer

b solve you mean?

anonymous · Answer

most likel;y differentiate

anonymous · Answer

with the cubic power over 3

amistre64 · Answer

$$\frac{8}{3}x^3-\frac{5}{12}x$$
like this equation?

amistre64 · Answer

....i meant expression :)

anonymous · Answer

Exactly like that equation .

amistre64 · Answer

and by solve; factor it?

anonymous · Answer

Well, I am supposed to find the sum or difference and put it in simple form, I dint see exactly what to factor in the expression.

anonymous · Answer

I dont kow why a teacher wuld ask you to factor that lol

anonymous · Answer

its pointless, all you can do is take out an x

amistre64 · Answer

since its asum of differeing powers of x; there is no way to add it

amistre64 · Answer

$$\frac{1}{3}x(8x^2 -\frac{5}{4})$$
perhaps?

amistre64 · Answer

maybe even take out a 1/4

amistre64 · Answer

$$\frac{1}{12}x(32x^2-5)$$

anonymous · Answer

So you want me to distribute 1/12x ?

amistre64 · Answer

i dont want you to mess with it; but i see nothing else to do to it :)

amistre64 · Answer

$$\frac{8}{3x^3}-\frac{5}{12x}$$
perhaps this is the problem?

anonymous · Answer

That is silimar one of my choices except it looks like 32-5x^2 over 12x^3

anonymous · Answer

Yes, That was the problem.

amistre64 · Answer

...... now it can be both :)

amistre64 · Answer

i typed cant, im sure i did.  my personalitites are conspiring against me lol

anonymous · Answer

ohh hah , i was confused.

amistre64 · Answer

$$\frac{8}{3x^2}*\frac{4}{4}-\frac{5}{12x}*\frac{x}{x}$$
$$\frac{32}{12x^3}-\frac{5x}{12x^3}$$
$$\frac{32-5x}{12x^3}$$

amistre64 · Answer

that little 3x^2 is a typo; it should be 3x^3

anonymous · Answer

So you multiplied 4 on both sides and then x why? o:

amistre64 · Answer

you gotta read thru the typos; but you get the basic principals right?

amistre64 · Answer

the x^2/x^2 =1; so we change the way the fraction looks without changing its value; and that way we can get like bottoms

amistre64 · Answer

4/4 = 1 as well

anonymous · Answer

Okay I understand , Thanks a lot I was confused for quite a while.

amistre64 · Answer

:)  practice helps.  And no typos too...