Question

If f(x) = 2[to the power of x] + 2[to the power of negative x], find f(1), f(2) and f(-2). Is f(-6)= f(6)

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

f(1) = 3/2

Answer 3

f(1)=2+1/2=5/2
f(2)=4+1/4=17/4
f(-2)=1/4+4=17/4

Answer 4

the function is even so for all x f(x)=x(-x)

so f(6)=f(-6)

Answer 5

him is wrong here..

Answer 6

How did you get that answer though? :L

Answer 7

doing...

Answer 8

\[f(x)=2^x+2^{-x}\]\[f(x)=2^x+\frac{1}{2^x}\]now put the values of x..

Answer 9

So basically I just have to substitute the 'x' values for the equation, and that's it?

Answer 10

\[f(-x)=2^{-x}+2^{-(-x)}=2^{-x}+2^x=f(x)\]

Answer 11

yes...for example..

Answer 12

\[f(1)=2^1+\frac{1}{2^1}=2+\frac12=\frac52\]

Answer 13

Oh, I get it. That's all you need to do? ._.