Mathematics
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OpenStudy (anonymous):
find the domain of the function f(x)=square root of (1+x) over (1-3x)
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OpenStudy (anonymous):
numerator gives us x>=-1 and denominator gives us x>1/3 so taking the intercestion we get x>1/3
OpenStudy (anonymous):
im lost a little. do i just pick a number for x?
OpenStudy (anonymous):
x>1/3
OpenStudy (anonymous):
nope u just don't pick a number, u actually find the possible values for x and then take an intersection ...
OpenStudy (anonymous):
ok i see thanks
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OpenStudy (anonymous):
d'u actually get it ?
OpenStudy (amistre64):
\[f(x)={\sqrt{(1+x)} \over (1-3x)}\]
this equations domain?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
oh!!! then x != 1/3 is the answer
OpenStudy (anonymous):
see i gave my ansewr based on this equation sqrt((1+x)/(1-3x))
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OpenStudy (amistre64):
the sqrt function needs to stay positive; and the bottom x cant make it go to 0
OpenStudy (amistre64):
good notation helps ;)
OpenStudy (amistre64):
D: = [-1,1/3) U (1/3 , inf)
OpenStudy (anonymous):
k its in union intervals. thank you so much
OpenStudy (amistre64):
<........[-1..............(1/3)...............>)
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OpenStudy (amistre64):
yup :)
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
ok i see thanks
OpenStudy (anonymous):
im lost a little. do i just pick a number for x?