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Mathematics 9 Online
OpenStudy (anonymous):

find the domain of the function f(x)=square root of (1+x) over (1-3x)

OpenStudy (anonymous):

numerator gives us x>=-1 and denominator gives us x>1/3 so taking the intercestion we get x>1/3

OpenStudy (anonymous):

im lost a little. do i just pick a number for x?

OpenStudy (anonymous):

x>1/3

OpenStudy (anonymous):

nope u just don't pick a number, u actually find the possible values for x and then take an intersection ...

OpenStudy (anonymous):

ok i see thanks

OpenStudy (anonymous):

d'u actually get it ?

OpenStudy (amistre64):

\[f(x)={\sqrt{(1+x)} \over (1-3x)}\] this equations domain?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

oh!!! then x != 1/3 is the answer

OpenStudy (anonymous):

see i gave my ansewr based on this equation sqrt((1+x)/(1-3x))

OpenStudy (amistre64):

the sqrt function needs to stay positive; and the bottom x cant make it go to 0

OpenStudy (amistre64):

good notation helps ;)

OpenStudy (amistre64):

D: = [-1,1/3) U (1/3 , inf)

OpenStudy (anonymous):

k its in union intervals. thank you so much

OpenStudy (amistre64):

<........[-1..............(1/3)...............>)

OpenStudy (amistre64):

yup :)

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

ok i see thanks

OpenStudy (anonymous):

im lost a little. do i just pick a number for x?

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