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Mathematics 7 Online
OpenStudy (anonymous):

Any idea how do you solve this one ? \[limit x \rightarrow \infty \sum_{K=1}^{n} \ln (1 + K/n)^{1/n}\] The answer is \[\ln (4/e)\]

OpenStudy (owlfred):

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

OpenStudy (anonymous):

actually n-> infinity rite?

OpenStudy (anonymous):

Oh yes I am sorry. It's limit n -> infinity not x

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