Question

solve for n:

squareroot(n+5)= n-1

Answer 1

i got 4?

Answer 2

n+5=n^2+1-2n
=>n^2-3n-4
n=4,-1 but n=-1 is not possible...so n=4 only.

Answer 3

squre both sides n+ 5) =(n -1)^2
n^2 - 2n + 1 -n - 5 = 0
n^2 -3n -4 = 0
x = 4 or -1

Answer 4

why isn't -1 possible?

Answer 5

squaring both sides u get n+5 = (n-1)^2
so n+5 = n^2 - 2n +1
0= n^2 - 2n -n +1 -5
0 = n^2 -3n -4
0 = n^2 -4n+1n-4
0=n(n-4)+1(n-4)
0=(n+1)(n-4)
now this product can be zero if either (n+1) is zero or if (n-4) is zero

if n+1 = 0 then n= -1
if n-4 =0 then n = 4

so u hv two value of n i.e -1 and 4

Answer 6

yes - -1 is possible

Answer 7

if we put n = -1 we get
squareroot (-1+5) = -1-1
squareroot (4) = -2
this is a valid answer becoz (-2)^2 = 4 !!!!

Answer 8

agreed

Answer 9

so both n = 4 and n= -1 are valid

@brackett
what is your view on this ?????