Question

the limit as t->0 (1+2t)^-(3/t)

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

e^(-2/3)

Answer 3

nope...him is right... :)

Answer 4

e^(-6)

Answer 5

how did you get that? I beleive e^-6 is right

Answer 6

as in e^-6 is the answer...

Answer 7

i get e^-6 as well

Answer 8

e^limit((-3/t)ln(1+2t))

Answer 9

then use L'Hopitals rule

Answer 10

e^limit((-3/t)ln(1+2t)) I need to review the exponent rules to find this. this is key, I can use L'H no problem.

Answer 11

u hav this formula....

lim x->0 (1+f(x))^g(x)=e^(lim x->0 g(x)*(f(x)) , only when f(x)->o and g(x)->infinity wen x->0

Answer 12

hmmm cant find where to give "Good answer"

Answer 13

it is in line with the poster's name

Answer 14

experiment try refreshing the page if you don't see the button

Answer 15

no button on right

Answer 16

k

Answer 17

got it thanks

Answer 18

yw

Answer 19

:)