Question

lim t->0 from the right of (1-Ln(t))/e^(1/t)

Answer 1

apply l'hospital rule and simplify.

Answer 2

0

Answer 3

i did, got 1/t// e^1/t*(-t^-2)... the series gets larger and larger

Answer 4

from the left = infinity

Answer 5

Cyter why do you say 0?

Answer 6

unless i'm wrong the lim is infinite/infinite so as Brackett said we use Hospital's rule
lim x--> 0 from the right of [(1/t)/(-e^1/t^1/t^2)=0

Answer 7

the series got bigger and bigger because u applied l'hospital wrongly...u need to stop applyin l'hospital, wen u don't hav its 0/0 or infinity/infinity form...u'll get 0.

Answer 8

i cant recall, is 0/inf a legitimate answer?
don't I need L'H again?

Answer 9

you need l'hopital's rule when you only have an indeterminate form as the limit

Answer 10

0/infinity = 0

Answer 11

i thought 0/inf was indeterminate....I think thats my problem

Answer 12

thanks.

Answer 13

see wenever u come across any indeterminate form, think for urself , wy can't u determine its value.
take the case of 0/inf
we hav 0/2=0/17=0/10239870870 as 0. then wy should u hav doubt on 0/inf.
dividing reduces value, wen u divide by inf. it totally reduces the value to 0.
don't get confused by the presence of o and inf together :)

Answer 14

Excellent explanation Brackett, i was indeed getting confused.