Question

(y+6/y+3)=(y-2/y-1)+1

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

I would suggest multiplying both sides of the equation by the common denominator (y+3)(y-1) and see what you have after that.

Answer 3

\[\frac{y+6}{y+3}(y-1)(y+3)=\frac{y-2}{y-1}(y-1)(y+3)+1(y-1)(y+3)\]

Answer 4

(y+6)(y-1)=(y-2)(y+3)+(y-1)(y+3)

Answer 5

I'd say they can take a stab at it from there myin.

Answer 6

k polpak hi by the way

Answer 7

=)

Answer 8

Thank you to both of you! :-)

Answer 9

I apologize but I am not sure where to go from the last post that myin put. Do I combine the (y+3)'s and make it 2(y+3)?

Answer 10

\[y^2+5y-6=(y+3)[(y-2)+(y-1)]\]
\[y^2+5y-6=(y+3)(2y-3)\]

Answer 11

And this is for solving for y?

Answer 12

isn't that what you wanted to do here?
i assumed u wanted to solve for y

Answer 13

Yes that is what I need to do for the problem but I am getting confused. I apologize.

Answer 14

You foil out those products, combine like terms, move everything to one side (equals 0) and solve the quadratic.

Answer 15

where?

Answer 16

Ok. Let me see if I get the right answer. Thank you.

Answer 17

If you have questions about a step feel free to ask.

Answer 18

But try stuff before you ask and explain why you're stuck.

Answer 19

should I get y=-1,3?