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limit as x goes to 0: (3x)/(cot(4x))
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change cot right?
You can. lim x->0 (3x)(sin(4x))/(cos(4x) Which gives you zero.
why is that though?
Because 3(0)sin(0)/cos(0)=0/1 or just 0.
oh, I see you substitute x in this case because it can not be factored or broken down any further
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thanks!
\[{3x \over cot(4x)} = {3x \over {1 \over tan(4x)}} = 3x (tan(4x)) = {3x(sin( 4x))\over cos(4x)}\]
And then yeah the limit of a quotient is the quotient of the limits. cos(4x) goes to 1, 3x goes to 0, sin(4x) goes to 0. So you have 0 over 1 which is 0.
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