This is Geometry: Write an equation of a circle with center (6,-9) and diameter= 2 sqrt of 7
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OpenStudy (anonymous):
So this is just like the last one you did except you have the diameter instead of the radius. Can you find the radius using the diameter?
OpenStudy (bbb911):
no im stupped :(
OpenStudy (anonymous):
The diameter is two times the radius.
OpenStudy (anonymous):
You aren't stupid. You just have to try.
OpenStudy (bbb911):
i am in math i always fail :( in english im really good at it
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OpenStudy (anonymous):
If you fail it is because you aren't trying. So if the diameter is 2 times the radius, how can you find the radius?
OpenStudy (bbb911):
even if i try :( did that once ended up gettting a D :(
OpenStudy (anonymous):
You aren't dumb.
OpenStudy (bbb911):
:(
OpenStudy (anonymous):
So if the diameter is 2 times the radius, and the diameter is 2 times sqrt(7) what is the radius?
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OpenStudy (bbb911):
4?
OpenStudy (anonymous):
No.
OpenStudy (anonymous):
\[D = 2(r)\]\[D = 2(\sqrt{7})\]
What is r?
OpenStudy (bbb911):
6
OpenStudy (anonymous):
Look at what I wrote.. What is different about those two lines?
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OpenStudy (anonymous):
The only difference is that one had an r and one had a \(\sqrt{7}\)
OpenStudy (anonymous):
Doesn't it seem likely that r is \(\sqrt{7}\)
OpenStudy (bbb911):
ohhhhhh ok so the radius is 7
OpenStudy (anonymous):
No, the radius is the square root of 7.
OpenStudy (bbb911):
say its sq 8 it would the r would be sqrt of 8 to?
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OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
D = 2(r)
If someone tells you that D is 2\(\sqrt{8}\) Then you know that r is\(\sqrt{8}\)
OpenStudy (bbb911):
oh i get it now
OpenStudy (bbb911):
oh ok sounds good
OpenStudy (anonymous):
If I tell you D is 10, then 2r = 10 so what is r?
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OpenStudy (bbb911):
10
OpenStudy (anonymous):
no
OpenStudy (anonymous):
D = 10
OpenStudy (anonymous):
2r = 10
OpenStudy (anonymous):
r = ?
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OpenStudy (bbb911):
2
OpenStudy (anonymous):
If 10 is 2 times r, then isn't r half of 10?
OpenStudy (bbb911):
half of 10 ?
OpenStudy (anonymous):
Ok, lets look at it this way.
If I tell you I'm thinking of a number. And I won't tell you what that number is.. We'll call it r.
OpenStudy (bbb911):
oh ok
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OpenStudy (anonymous):
Now I tell you that if you take my number 'r' and multiply it by 2 you will get 12. Can you tell me what the number I'm thinking of is?
OpenStudy (bbb911):
10
OpenStudy (anonymous):
2 times 10 is 12?!?!
OpenStudy (bbb911):
ooo wait i messed up
OpenStudy (bbb911):
its 6
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OpenStudy (anonymous):
Right! Are you a psychic!?!? How did you know?
OpenStudy (bbb911):
i just times 6 and 2 hehe
OpenStudy (anonymous):
That's a hard way. You have to guess a lot. Couldn't you just divide 12 by 2?
OpenStudy (bbb911):
yea so true
OpenStudy (anonymous):
Ok. So lets play the guessing game again.
I'm thinking of a radius. I wont tell you ! It's a secret! Shh..
But I will tell you that the diameter is 64. And that diameter is 2 times my radius. What is my radius?
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OpenStudy (bbb911):
32
OpenStudy (anonymous):
OMG you are a psychic! I knew it!
OpenStudy (bbb911):
yaya:D
OpenStudy (anonymous):
Just to prove your mental powers we'll do one final one.
I'm thinking of a radius. The diameter (2 times the radius) is \(4\sqrt{3}\). What is the radius?
OpenStudy (bbb911):
okay thats a bit harderder
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OpenStudy (anonymous):
But not too hard.
OpenStudy (anonymous):
What does \(4\sqrt{3}\) mean?
OpenStudy (bbb911):
the r is 3
OpenStudy (anonymous):
No.
OpenStudy (anonymous):
It's a bit tricky but I think you can do it.
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OpenStudy (anonymous):
What does \(4\sqrt{3}\) mean?
OpenStudy (bbb911):
4 sqrt of 3
OpenStudy (anonymous):
Right. But that _means_ you have four \(\sqrt{3}\) added together. It also _means_ \(4 \times \sqrt{3}\)
OpenStudy (anonymous):
So can you figure out what:
\[4\times \sqrt{3}\div 2 =\ ?\]
OpenStudy (anonymous):
\[4\times \sqrt{3}\over 2\]
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OpenStudy (bbb911):
that would be 6 then
OpenStudy (anonymous):
no.
OpenStudy (anonymous):
\[{4(\sqrt{3}) \over 2} = {4 \over 2}(\sqrt{3})\]
OpenStudy (anonymous):
What is 4/2?
OpenStudy (bbb911):
oh 2
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OpenStudy (anonymous):
So what is
\[{4 \over 2}(\sqrt{3})\]
OpenStudy (anonymous):
Taking too long.. You must have gotten confused.
If 4/2 IS 2
Then (4/2) times sqrt(3) IS 2 times sqrt(3)
OpenStudy (bbb911):
umm a lil
OpenStudy (anonymous):
Read what I wrote. Out loud if needed.
OpenStudy (anonymous):
Sometimes it helps to hear things than to see them.
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OpenStudy (bbb911):
oh both 4 and 2 time sq 3
OpenStudy (anonymous):
No.
OpenStudy (bbb911):
then im confused
OpenStudy (anonymous):
4 divided by 2 IS 2.
6 divided by 2 IS 3.
(4 divided by 2) times (sqrt 5) IS 2 times (sqrt 5)
(6 divided by 2) times (sqrt 27) IS 3 times (sqrt 27)
OpenStudy (anonymous):
If 4 divided by 2 is exactly the same thing as 2 then any time you see 4 divided by 2 you can just write a 2 there instead.
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OpenStudy (bbb911):
oh i think answer should be 28=(x+6)sq + (y-9)sq am i correct?
OpenStudy (anonymous):
Nope.
OpenStudy (anonymous):
Close
OpenStudy (bbb911):
does the 6 have to be negative and the nine positive?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Also your radius is wrong.
OpenStudy (bbb911):
ok is the answer 7=(x-6) sq + (y+9)sq
OpenStudy (anonymous):
Yes
OpenStudy (bbb911):
yaya i did it :3
OpenStudy (anonymous):
=)
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OpenStudy (bbb911):
thanks so much for your help
OpenStudy (anonymous):
Of course. I suggest that if you get some free time you practice some simple equations. I think if you invest a little time in the areas you need work you will find solving these other problems much much easier.
OpenStudy (bbb911):
yea thats true thanks for the advice its very helpful