help! intergration by parts: when do you stop intergrating? If it is until your next intergration give you zero, then what about the special cases (e.g.: e^x) -- Thanks So much!
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Also, how do i bump?
use until you solve it :) any example?
e.g.: when do i stop intergrating when i do intergration by parts
e.g. e^x is an infinite "loop"
\[\int\limits_{ }^{ }e ^{x}dx=e ^{x} +c\]
something like: \[\int\limits_{}^{} X^3*e^x\]
i get (x^3)(e^x) - (3x^2)(e^x)-6x*e^x-6x*e^x-6\[\int\limits_{}^{}e^x\]
and the last step is: -\[\int\limits_{}^{}6*e^x\]
so isn't that an infinte loop cause i gotta intergrate until i get zero
this will require few of those! 1) u=x^3, dv=e^x \[=x ^{3}e ^{x}-3\int\limits_{ }^{}x ^{2}e ^{x}dx=...\]
i only know f(x) and g(x) method =(
\[=x ^{3}e ^{x}-3x ^{2}e ^{x}+6\int\limits_{ }^{}xe ^{x}=... and one more time.. will be done!\]
it's just a matter of names... g,f, u or v... what ever you call it.
but when i do intergration by parts, i never stop b/c i dont know when to. If my next intergration gets to zero, i know to stop, but there are infinte loops like e^x
i don't understand what you mean... :( can you finish your example? it's not = 0
\[=x ^{3}e ^{x}-3x ^{2}e ^{x}+6xe ^{x}-6e ^{x}+const\]
kk so: when you intergrate something and you have to intergrate again and again, the only way i know to stop is when i hit zero. But i never stop when i intergrate something that is a "loop" like e^x (b/c u can derive e^x for ever and still get e^x). I'm confused when to stop intergrating something.
did you get how to do integration in your example? Do you have another one that I can see what you mean?
yes i know the basics, but repitive intergration is where i run into trouble b/c i dont stop intergrating.
ill look for antother example
Normally I integrate until I find the solution. Even "loop" could be beneficial (like in sin^n & cos^n integration)...
but how do you know when to stop? that's my problem.
you don't... :) unless it can not be solved... some integrals could be founded only by table or computer programming... I don't think in regular Calculus program they will put something like that
so there is no hard fast rule? just stop when it can't be solved? if so im sooooooooooo stupid
no "fast "rules...that I know of :( I just go by the "rule", that the problems in a book & on a test - have to have solution. In real life - bummer!
well thanks for all your help :) you rock
you too! if you got to Calculus... you rock!
nah u do, u can explain it :)
thnx & good luck!!
ty u 2
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