Question

I am trying to solve the problem: 3(2-4)(squared) + the absolute value of 2-5
Sorry I don't know how to use the subscript for the squared.

Answer 1

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Answer 2

do what is inside the parens first, so 2-4.

3(-2)^2 + abs(2-5) ---> I fixed inside the parens
3(4) + abs(2-5) ---> I applied the exponent to (-2)
12 + abs(2-5) ---> I multiplied out the left side
12 + abs(-3) ---> I fixed inside the parens on the right side
12 +3 =15 ---> I took the absolute value of (-3), which is three, and added it to 12.

final: 15

Answer 3

So you don't multiply the 4 by the exponent?