how do you get the inverse of this function? f(x)= 1/x+2
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Set \[x = \frac{1}{y+2} \] and solve for y
get \[xy + 2x = 1\]
so \[y = \frac{1-2x}{x} = \frac{1}{x} - 2 \]
that is the inverse function
but how do you simplify the 1/y+2? sorry, i'm so bad at math.
Well, the original function was \[\frac{1}{x+2}\] If you take the reciprocal of this you get \[x+2\] then if you subtract 2 you get \[x\], which is the identity function
so the inverse function is "take reciprocal and subtract 2"
that is , \[ \frac{1}{x} - 2\]
ah that makes complete sense. thanks so much!!!
No problem :) good luck with the rest of your work
oh thansk! actually, one last question; when solving for inverses what are the usual steps you take? do you just switch x and y and simplify from there or...?
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