Question

roots for x^3-6x^2+7x-2 HELP

Answer 1

please

Answer 2

are they 1 and 2?

Answer 3

anyone?

Answer 4

By trial, we can easily find that \(1\) is a root of the given polynomial, and therefore \(x-1\) is a factor of it. Using long division to divide \(x^3-6x^2+7x-2\) by \(x-1\), we find that \(x^3-6x^2+7x-2=(x-1)(x^2-5x+2)\). That means the polynomial has also the roots of the quadratic equation \(x^2-5x+2\), which are \(\frac{1}{2}(5+\sqrt{17})\), and \(\frac{1}{2}(5-\sqrt{17})\).

Answer 5

gblover i answer this on your other q..lol