Question

Directions : solve the problem

a coin is placed 0.15 m from the center on a turntable that turns once every 1.8 seconds.

Answer 1

rest of the problem?

Answer 2

Calculate the Velocity of the coin

Answer 3

the angular velocity (the angle in radians it travels per second) would be 2 pi radians in 1.8 seconds... the tangential velocity would be the distance it travels divided by the time which would be 2 pi (0.15 m) / (1.8 s). note the velocities are related... \[v = \omega * r\], where v is the tangential velocity, \[\omega\] is the angular velocity and r ios the distance from the axis of the rotating object

Answer 4

using the same problem it says calculate the acceleration of the coin ?

Answer 5

since the speed is not changing, the acceleration must be causing the direction of the velocity vector to change. there are lots of places where the derivation of this type of acceleration is done, so I won't bother, but this type of acceleration is called centripetal acceleration - meaning center-directed. the magnitude of it is given by\[v ^{2}/r = (r \omega)^{2}/r = \omega ^{2}r\] so just plug in your values from above