Question

hi every1, i have an question that im struggling for some time already and i cant find the answer.

A cafeteria have 500 clients a day, it sells the coffe for 2,50 dollars, for each 0,05 increase on the price they lose 10 clients, get the maximun profit possible ?

Answer 1

its in british units; I can see why you was confused

Answer 2

its linear

Answer 3

2.50 + .05n = 500 - 10n is what I see

Answer 4

well; they aint 'equal' in the regards... just proportional

Answer 5

500 * 2.5 = 1250
450 * 2.75 = 1237.5

Answer 6

that doesnt look right.....

Answer 7

1250.00
1249.50
1248.00
1245.50

Answer 8

well; max profits appear to be at a price of 2.50 and equal 1250

Answer 9

I know what I was thinking now lol

P(n) = (500-10n)(2.50+.05n)

Answer 10

You've probably confused him more than he initially was, haha.

Answer 11

:) you might be right

Answer 12

the way i tought it was going to to be right was trial and error.
just like this 500 x 2,25 and then 490 x 2,30 and keep going

Answer 13

but its grade 10 math so i guess i need to use some formula like renevue ...forumula

Answer 14

C = 500 - 10*n
V = 2.50 + 0.05*n
P = C * V
\[P = (500-10n)*(2.50+0.05n) = 1250 - 0.5n ^{2}\]

We can observe that to P be the maximum value, we need to put n=0. So, the answer is not increase the value of coffe.

Ps.: If is in BRZ, 2.50 is a good price for a good coffee and with a good profit. ;-)