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Mathematics 8 Online
OpenStudy (anonymous):

e^(x+2) = e^(x) + 5

OpenStudy (anonymous):

\[e^{x+2}=e^2e^x\] should be a good start

OpenStudy (anonymous):

\[e^2e^x-e^x=5\] \[e^x(e^2-1)=5\] \[e^x=\frac{5}{e^2-1}\]

OpenStudy (anonymous):

take the log to get \[x=\ln(\frac{5}{e^2-1})\]

OpenStudy (anonymous):

k?

OpenStudy (anonymous):

great! thank satellite783

OpenStudy (anonymous):

yw

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