i am wonder if i did this correct. (6x+7)(3x+2) = 13?
What did you get?
i got 13
18X^2+33X+1=0
Then no. You have x terms in there that aren't gonna go away.
Are you given (6x+7)(3x+2) and asked to simplify? Or is it an equation?
multiply
Quadratic formula, anyone?
Right. So you have to distribute.. \[(6x+7)(3x+2) = 6x(3x+2) + 7(3x+2)\] And then distribute again.
@dheeraj how did u get 0?
It's not an equation. You can't solve it using the formula.
Woops, my bad wasn't really paying attention.
dheera thought you were working with the equation (6x+7)(3x+2) = 13
But you aren't, so his solution is not what you want.
i guess i right after all
No you aren't
i wasnt ....so the answer is not 13 ?
No. I already said that, and explained how to find the expanded form.
YEP I THOUGHT OF QUADRATIC EQUATION
If you review this thread it was not an equation. It was simply a multiplication problem. So you won't have to use quadratic formula.
exactly let me give u an example: (5x+2) (7x-3) = 35x^2-x-6
Yes and from what polpak provided you will get;\[18x ^{2}+33x+14\] provided i multiplied correctly
Did you get that also?
yes but i am trying to figure out how is that possiable
Some people use what they call FOIL. I like to do it the old fashion way 6x+7 times 3x+2 ---------------- 12x+14 18x^2+ 21x ----------------- 18x^2+33x+14
i got it did i guess i didnt mine the wrong way
I don't like foil or the 'old fashioned' way. I just distribute. \[(6x+7)(3x+2) \]\[= 6x(3x+2) + 7(3x+2)\]\[=18x^2 + 12x + 21x + 14\]\[=18x^2 + 33x + 14\]
That looks like a simpler way than FOIL
And it works when there's more than 2 terms!
thanks guys
Very good, a simple and to me a novel method. I never did like FOIL
It's not really novel.. You do it all the time for monomials. It's just a continuation of standard distribution. \[3b(2c+d) = 3b(2c) + 3b(d)\] But if b = (f+g) We still get the right thing
ok sounds good
ok i got another (4x+1)(2x^2+x+1)
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