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how far is the point (5,-12) from the origin?
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13 units
17 units
Go over 5, at 0, then up 12 so it's all connected. 5+ 12 = 17 units
no...
the distance formula is \[d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\] and plug in the coordinates and you have your answer.
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the formula is..\[\sqrt{(x1-x2)^2+(y1-y2)2}\]
dipankarstudy it's \[d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\]
theres only one coordinate
the coordinates of the origin is (0,0)
No, they're right. The other cordinate is (0,0) it's 13..I wasn't thinking.
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so we have \[d= \sqrt{(-12-0)^2+(5-0)^2}\]
you solve that and you get \[d=\sqrt{144+25}\]
\[d=\sqrt{169}\] and square root of 169 is 12
...No it's 13.
oops sory i ment 13
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