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Mathematics 8 Online
OpenStudy (anonymous):

how far is the point (5,-12) from the origin?

OpenStudy (anonymous):

13 units

OpenStudy (anonymous):

17 units

OpenStudy (anonymous):

Go over 5, at 0, then up 12 so it's all connected. 5+ 12 = 17 units

OpenStudy (anonymous):

no...

OpenStudy (anonymous):

the distance formula is \[d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\] and plug in the coordinates and you have your answer.

OpenStudy (anonymous):

the formula is..\[\sqrt{(x1-x2)^2+(y1-y2)2}\]

OpenStudy (anonymous):

dipankarstudy it's \[d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}\]

OpenStudy (anonymous):

theres only one coordinate

OpenStudy (anonymous):

the coordinates of the origin is (0,0)

OpenStudy (anonymous):

No, they're right. The other cordinate is (0,0) it's 13..I wasn't thinking.

OpenStudy (anonymous):

so we have \[d= \sqrt{(-12-0)^2+(5-0)^2}\]

OpenStudy (anonymous):

you solve that and you get \[d=\sqrt{144+25}\]

OpenStudy (anonymous):

\[d=\sqrt{169}\] and square root of 169 is 12

OpenStudy (anonymous):

...No it's 13.

OpenStudy (anonymous):

oops sory i ment 13

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