Question

Rationalize the denominator.

\[10-\sqrt{3} / 10+\sqrt{3}\]

Answer 1

multiply numerator and denominator by conjugate of denominator

Answer 2

\[\frac{10-\sqrt{3}}{10+\sqrt{3}}\times \frac{10+\sqrt{3}}{10+\sqrt{3}}\]

Answer 3

oops all that and i wrote ti wrong

Answer 4

(10-root3)^2/91

Answer 5

\[\frac{10-\sqrt{3}}{10+\sqrt{3}}\times \frac{10-\sqrt{3}}{10-\sqrt{3}}\]

Answer 6

get what mr. knowledgeable said. on account of
\[(10+\sqrt{3})(10-\sqrt{3})=10^2-\sqrt{3}^2=100-9=91\]

Answer 7

now
\[(10-\sqrt{3})(10-\sqrt{3})=10^2-20\sqrt{3}+3=103-20\sqrt{3}\] if you want that in the numerator