Can someone explain to me why 2/5-3=2/5-15/5?
15/5=3 so when you subtract either of them from 2/5, you get the same answer.
I don't understand why 3=15/5. I'm very confused as to why the whole number becomes that fraction and how do you know what the fraction value will be.
15/5 means ... 15 divided by 5 does 15 divided by 5 = 3?
\[\frac{15}{5}\Longleftrightarrow 15\div 5\]
OHH OK!!! So the fraction will always be whatever the division problem would be to get the whole number?
we also know that 3*1 = 3 and that 5/5 = 1 \[\frac{3}{1}*\frac{5}{5} = \frac{15}{5} = 3\]
yes; fractions are just dividing
12/3 = 4 18/9 = 2
You are a God sent!!! I have been so stressed over this work!!! Would you mind working through one problem with me so I know what I am doing?
post it and lets see
and if you have any white out handy; just erase that "group master" jargon .... its soo misleading
Lol. I was so confused by that!
Find the equation of the line having the given slope and containing the given point. m=6 (9,1). The equation of the line in slope-intercept form is y=?
y=6x-53
it is just an lcm concept (2/5) + 3 on taking lcm it becomes (2 + 15)/5 ,then you split it into two 2/5 +15/5 hence they are equal
its simple\[3*5\div1*5\]
the point P(x,y), in this case (9,1) and the slope m = 6, here y = m(x-Px)+Py
y=2x+8?
y = 6(x-(9))+1 y = 6x -6(9) + 1 y = 6x -54 +1 y = 6x -53 is what I get for point intercept form
Forget what I just typed, that was the example problem. I get mixed up having to go back and forth!
y=6x-53?
m= 6; P(9,1); slope intercept form: y = 6x -53 by the steps i took
The next one is harder...
lol ..... bring it on!! :)
m=8/9, (8,-3)
not harder; just different numbers :) y = mx -mPx +Py perhaps :)
y = (8/9)x -(8/9)*8 -3
would it be y+3=8/9x-4/2? Or am I wrong again on the fraction?
y = (8/9)x -64/9 -27/9 y=(8/9)x - 91/9
Why was it 91/9?
this is the part your having difficulties with \[-(\frac{8}{9}*\frac{8}{1})-(\frac{3}{1}*\frac{9}{9})\]
all ths amounts to is this: \[\frac{-64-27}{9}\]
I feel like an idiot because my brain just won't wrap around the fraction part of it!
its important to remember that in order to add or subtract fractions; they need to be wearing the same pants.... otherwise they dont want to talk to each other...
multiplying fractions? they are fine with that .... but to join the group? you gotta have the right clothes on
what number can we multiply by that doesnt change the value of a number?
8 * ? = 8?
1
thats right; 1 seems pretty useless; but it really how we WRITE '1' that matters
So figure out the simplified fraction?
does anything over itself = 1? 3/3 = 1 ? 125/125 = 1 ? b/b = 1 ?
yes
so we have a way in which we can "multiply" by '1' and change the way a fraction LOOKS; but keeps the same value right?
Thank you dearly for your patience with me!
yes
so lets use that to our advantage :) - 8 8 -64 --- * -- = ---- right? 9 1 9
Yes!
but we get stuck here; becasue they arent wearing the same pants right? -64 3 ---- - --- 9 1
This is where I get lost. How do you know that they aren't wearing the same pants? Again, sorry for all the questions. I just really need to learn and understand everything.
-64/9 has on a 9 under it; its pants are a size '9' -64/9 ; pants are properly called a denominator 3/1 has a 1 under it; its pants are a size '1' right?
yes
so lets see if there is any outfits in the closet to redress the 3/1 in to match the pants of -64/9 1 * ? = 9 ??
9
good; we have something that fits :) 3 9 27 -- * -- = --- <-- now we are dressed to mingle with the -64/9 1 9 9
-64 -27 -64-27 -91 --- + ---- = ------- = ---- <-- this is true right? 9 9 9 9
yes
do you see how that happened tho?
so you can multiply something with the one that doesn;t fit to make to match?
yes.... fractions will multiply like rabbits with no regard for what they look like.....
Ok, do you mind moving onto the next problem or do you need to go?
as long as you are getting the principals underneath this fraction stuff; im good to go to the next one :)
OK, here we go.... :)
Find an equation of the line containing the given pair of points. (-2,-4) (-8,-1)
'an' equation? no particular form?
I got a slope of -3/6. Is that right?
m=y2-y1/x2-x1= is the formula
slope = (change in y)/(change in x) and I like to stack my points to keep track of them: ( x , y ) (-2,-4) -(-8,-1) -------- ( 6, -3); slope = y/x = -3/6 = -1/2
So always simplify the answer?
always? ..... most math tests and class WANT you to so yeah.
-3/3 -1 ----- = ---- 6/3 2
So then we would move onto, y-(-1)=-1/2(x-(-8))
yes; for point slope form of a line that would be good
y+1=-1/2x+4?
.... -4
-1/2x8/1=8/2 or 4?
-1 8 -8 --- * --- = ---- = -4 2 1 2
y=-1/2x-3?
close.... y+1 = (-1/2)x -4 -1 -1 ----------------- y =(-1/2)x -5
y=-1/2x-5!
thats better :)
Write an equation in standard form of the line passing through the given pair of points. The line goes through (2,4) (2,2). what is the equation? x+y=4 x=2 y=4 or undefined
A whole new equation to confuse me, lol.
well; I can see that the x parts are the same; so it really doesnt matter what the y parts are.... (2,y) satisfies this; so, x=2
So if the x's are the same, it would just be x=whatever the number is?
thats right; since x always = that number; the equation is: x = that number :)
:) I am beginning to get a little more confident!
write an equation of the line containing the given point and parallel to the given line. (9,-2); 6x-7y=4. the equation of the line is y=?
Would I plug in the points of the x and y in the equation 6x-7y=4 or 6(9)-7(-2)=4?
parralel points hav ethe same equation; just a different 'sum'; so ignore the "=4" part and fill in your x and y values to get a new one
Wow! I am wrong on this one!
6(9) -7(-2) = new sum for parallel line 54 +14 = n 68 = n 6x -7y = 68
you probably missed your sign
Now, I have to figure out the slope so I can continue to y=?
why ? what form of the line equation you need?
The help topics first suggestive step is 6x-7y=4 should be to subtract 6x from both sides.
So -7y=4-6x?
6x -7y = 68 is an equation for a line y+2 = -6/7(x-9) is the same line y = -6/7x +68/7 is the same line 6x 7y --- - --- = 1 is the same line 68 68 there are many "forms" for the equation of a line to take; and all of them are equally valid
....and I missed the -7 in my head lol
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