Question

Graph f (x) = x2 − 4 3x + 9

Answer 1

Is it \[f(x)=(x^2-4)(3x+9)\]

Answer 2

it is subtract

Answer 3

not multiply

Answer 4

\[f(x) = x^2 - 43x+9\]???

Answer 5

f(x) = (x2-4)/(3x+9)

Answer 6

It's very helpful if you use the equation editor to say specifically what you mean ;)

Answer 7

f(x) = \[{x^2-4\over 3x+9}\]

Answer 8

That it?

Answer 9

yes

Answer 10

Do you want to do this by hand or with a calculator?

Answer 11

with by hand

Answer 12

Have you found the vertical asymptote?

Answer 13

I forgot a resolve

Answer 14

I'm sorry, I don't understand.

Answer 15

you can help me write the answer

Answer 16

Ok, to graph this by hand you'll need to find the following:
1.) vertical asymptote(s) (if any)
2.) holes (if any)
3.) horizontal asymptote (if any)
4.) slant asymptote (if any)
5.) x- and y-intercepts
6.) some other points to help fill in the detail

Answer 17

1.) to find the vertical asymptote you need to set the denominator equal to zero and solve for x.
\[3x+9 = 0\]

Answer 18

Post your answer when you get it so I can see you're on the right track :)

Answer 19

x=-3

Answer 20

great. We need to make sure that x=-3 is actually a VA and not a hole. To do this we need to substitute -3 into the numerator to see if we get 0. If we get 0 then x=-3 is a hole, if we don't get 0 then x=-3 is a VA.
\[(-3)^2-4 =? \; 0\]

Answer 21

So is it a hole?

Answer 22

I can't find the answer

Answer 23

What number do you get as an answer to the following:
\[(-3)^2-4\]