Question

find the 5th term of the sequence which has a first term of 17 and has a common ratio of 3.1.

Answer 1

n=5-1
=4
17(3.1^4)
=1570

Answer 2

\[a \times r^n\] where a is the first term and r is the common ratio n is the number of the term

Answer 3

A{1} = 17 ; and a geometric ratio o f 3.1

A{2} = 17 * 3.1

A{3} = 17 * (3.1 * 3.1)

A{4} = 17 * (3.1 * 3.1 * 3.1); [3.1^3]

A{n} = 17 * 3.1^(n-1)

Answer 4

A{5} = 17 * 3.1^(4)

Answer 5

I get 1569.98... if i did it right

Answer 6

a(1) = 17
a(2)=52.7
a(3)=163.37
a(4)=506.447
a(4)=1569.986

Answer 7

except the last index should be 5! ha ha ha

Answer 8

lol