use the factor theorem and synthetic division to decide whether or not x-4 is a factor o f x^3-2x^2+x-1.
plug in 4 to see if the function evaluate to zero
synthetic division. write the coefficients 1 -2 1 -1
put a 4 on the side because you are dividing by x - 4 1 -2 1 -1 4 ________________________________________________
bring down the 1 1 -2 1 -1 4 _________________________________________________ 1
4 times 1 is 4 1 -2 1 -1 4 4 _________________________________________________ 1
-2+4=2 1 -2 1 -1 4 4 _________________________________________________ 1 2
4*2=8 1 -2 1 -1 4 4 8 _________________________________________________ 1 2
8+1=9 1 -2 1 -1 4 4 8 _________________________________________________ 1 2 9
4*9=36 1 -2 1 -1 4 4 8 36 _________________________________________________ 1 2 9
-1+36=36 1 -2 1 -1 4 4 8 36 _________________________________________________ 1 2 9 35
so the answer is no, it does not divide evenly. it leaves a remainder of 35
and in fact you now know that \[\frac{x^3-2x^2+x-1}{x-4}=x^2+2x+9+\frac{35}{x-4}\]
or to put it another way, \[x^3-2x^2+x-1=(x-4)(x^2-2x+9) +35
\[x^3-2x^2+x-1=(x-4)(x^2-2x+9) +35\]
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