Question

Show an equation and a solution for the problem. At noon, a train leaves Bridgetown heading east at 90 mph to Cartertown. Another train leaves Bridgetown at 1:00 p.m., also heading east at 100 mph. In how many hours after the second train left will they pass each other?

Answer 1

help please

Answer 2

90(x+1)+100x=time until they pass.(y)
solve for x
90x+90+100x=y
120x+90=y
120x=-90
x=-.75
i did something wrong. Harkirat hopefully will have the right answer.

Answer 3

By 1 pm the first train will be 90 mile ahead of the second train
Since the difference between the speeds is 10 mph, the second train will make up 10 miles every hour and so will take 9 hours to make up the 90 miles and hence catch up and pass the first train

So the second train will pass the first train after 9 hours

Answer 4

do you need it in the form of formulas???

Answer 5

yes.

Answer 6

for an equation you might right
\[1+90t=100t\] since distance = rate times time, and they obviously meet at the same time

Answer 7

that is wrong.

Answer 8

\[90+90t=100t\] is right i believe

Answer 9

What is wrong

Answer 10

what i wrote

Answer 11

first trains distance is 90 + 90t, second trains distance is 100t and they meet at the same time so you have
\[90+90t=100t\]

Answer 12

let the no of hours after which the second train catches the first one be = x hours
By this time the first train (which left earlier) would have been travelling for (x+1) hours

So, in (x+1) hours the first train will cover distance = 90(x+1) miles
and distance covered by the second train in x hours = 100x miles

But since the second train catches and passes the first after x hours, this means that above distances will be equal at that point
So, we get
90(x+1) = 100x
90x + 90 = 100x
90 = 100x-90x
90 = 10x
90/10 = x
so x=9
Hence the second train will pass the first train after 9 hours

Answer 13

My Medal !!!!??????

Answer 14

help me with my other question