Question

solve x^2+7x-10=0, find the intercepts of x

Answer 1

doesn't factorise, so use quadratic formula

Answer 2

(x^2 +7x +(49/4))-10-(49/4) = 0

(x+(7/2))^2 -89/4 = 0

x+(7/2) = +- sqrt(89)/2

x = -(7/2) +- sqrt(89)/2

maybe

Answer 3

\[x=\frac{-1\pm \sqrt{89}}{2}\]

Answer 4

if your job is to complete the square start
\[x^2+7x=10\]
\[(x+\frac{7}{2})^2=10+(\frac{7}{2})^2\]
\[

Answer 5

then
\[(x+\frac{7}{2})^2=10+\frac{49}{4}=\frac{89}{4}\]

Answer 6

then
\[x+\frac{7}{2}=\pm\frac{\sqrt{89}}{2}\]

Answer 7

and finally subtract to get
\[x=-\frac{7}{2}\pm\frac{\sqrt{89}}{2}\]
aka
\[x=\frac{-7\pm\sqrt{89}}{2}\]

Answer 8

just like amistre got