what are the formulas for an object in free fall mode?

Question

anonymous · Answer

derive urself...i guarantee u will have fun :P lol

amistre64 · Answer

lol

amistre64 · Answer

feet are -16(t^2) + initial velocity(t) + initial height

amistre64 · Answer

same for metric but the -16 turns to 4.something

anonymous · Answer

wherers the acceleration do to gravity?

anonymous · Answer

Acceleration by gravity is ~-9.81 m/sec^2. In amistre64's post (using imperial units) that's the -16 in front of the t^2 term, meaning -16 feet / second / second. The general form for motion along one axis is:
(Current Position) = (Original position) + (Original Velocity) x (Current Time) + (1 / 2) x (Current Acceleration) x (Current Time) ^2

This can be easily derived from basic Calculus, and I recommend learning how to derive it before you take too much advantage of the formula.