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if f(x)= 4/(x-2), find f '(4)
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think of it as 4(x-2)^-1, now differentiate using power rule -4(x-2)^-2
technically chain rule as well but d/dx(x-2) = 1
so 1 would be my answer?
f'(x) = -4/(x-2)^2 f'(4) means you replace x with 4 =-4/(4-2)^2 =-4/4 = -1
oh, ok. Thanks. for this function, how would you calculate the slope of the tangent line at the point (4,2)
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guess what you already did. f'(4) is the slope the tangent line at (4,2)
crap, not slope. I meant intercept.
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