Question

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given that the collision cross-section for the molecules of that gas is 2.0 ×10^-20 m2? Boltzmann's constant is k = 1.38 × 10-23 J/K.
A) 1.5 × 10-6 m
B) 2.1 × 10-6 m
C) 5.3 × 10-6 m
D) 1.1 × 10-6 m
E) 1.7 × 10-6 m

Answer 1

\[mean free path= (K_{B} T)/(\sqrt{2} \Pi D ^{2} P)\]

where K_{B} is Boltzmann constant
T is temperature
D is diameter of particle
p is pressure

Now you can calculate.