Question

Solve. Please show the algebraic inequality you used and please show work.
Two cell phone companies are advertising rates. Company A charges a rate of $20 per month plus $0.05 per minute. Company B charges a rate of $10 per month plus $0.10 per minute. What is the number of minutes used above which Company A costs more than Company B?

Answer 1

\[Cost(A)=20+.05t\]
and
\[Cost(B)=10+.1t\]
Where t is the number of minutes.
We know that the constraint asks for the time when Cost(A) is equal to Cost(B)
So the constraint is
\[Cost(A)=Cost(B)\]
The inequality they are looking for is
\[20+.05t \ge10+.1t\]
Solve and we get
\[.05t \le10\]
or
\[t \le200\]
Here, I realize that the cost of A is greater than the cost of B when the time is less than 200 minutes. When the time is above 200 minutes, the cost of B is greater.

Answer 2

thanks

Answer 3

np