Mathematics
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OpenStudy (anonymous):
Given that f(x)= absolute(2x+6)
determine where it is not differentiable?
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OpenStudy (anonymous):
at the corner
OpenStudy (anonymous):
not diff at 0
OpenStudy (anonymous):
oh yes it is
OpenStudy (anonymous):
nah man it isnt
OpenStudy (anonymous):
sure it is
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
absolute value of 2x + 6 =2x+6 if 2x+6 > 0 i.e if x > -3
OpenStudy (anonymous):
and of course it is -2x-6 if x < -3
OpenStudy (anonymous):
is continuous at -3, but has a corner there, so not differentiable at -3
OpenStudy (anonymous):
-2x-6 if x < -3
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OpenStudy (anonymous):
yah man
OpenStudy (anonymous):
i am confused on this one now?
OpenStudy (anonymous):
ok lets go slow
OpenStudy (anonymous):
\[|2x+6|\] is actually a piece-wise defined function, just as
\[|x|\] is
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OpenStudy (anonymous):
ok gotcha
OpenStudy (anonymous):
if what is inside the absolute values sign it positive, then it is just itself. for example if x = 2 then\[ |2\times 2 +6|=2\times 2+6\]
OpenStudy (anonymous):
on the other hand if what is in the absolute value sign in negative, it is the opposite of that
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
I understand absolute vlaue
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OpenStudy (anonymous):
it's the left and right calc that gets me
OpenStudy (anonymous):
for example if x = -5 then
\[|2\times -5+6|=-2\times- 5 - 6\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
in other words
\[|2x+6|=2x+6\] or
\[|2x+6|=-2x-6\]
OpenStudy (anonymous):
so you have two different lines, one with slope 2 and the other with slope -2. these are different, and they are your derivatives
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OpenStudy (anonymous):
finally! that is the right and left side calc correct?
OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
left being the minus 2x
OpenStudy (anonymous):
and where do they change?
OpenStudy (anonymous):
great I have it meow!
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OpenStudy (anonymous):
they change when
\[2x+6>0
\]
\[2x>-6\]
\[x>-3\]
OpenStudy (anonymous):
in other words they change at -3, so this function is not differentiable there
OpenStudy (anonymous):
dose that mean at -3?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
did you look at the picture i sent? you see a corner at -3
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OpenStudy (anonymous):
why in the left side calc is the 6 a minus? I thought that the only x would change signs?
OpenStudy (anonymous):
hold on
OpenStudy (anonymous):
it only opened to the home page with no equation, pic or anything else
OpenStudy (anonymous):
|x| is x if x >0 and -x if x < 0 ok with that?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
this means that
|2x+6| = 2x+6 if 2x+6 > 0 or -2x-6 if 2x+6<0
OpenStudy (anonymous):
i just replaced the "x" by "2x+6"
OpenStudy (anonymous):
ok with that?
OpenStudy (anonymous):
yes i see, so both signs must change - makes sense! thanks!
OpenStudy (anonymous):
but of course you have to answer in terms of x, not in terms of 2x+6
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OpenStudy (anonymous):
so if 2x+6>0 that means x >-3 and that is where this changes from 2x+6 to -2x-6
OpenStudy (anonymous):
that is where the slope changes from -2 to 2
OpenStudy (anonymous):
and so that is where your function is not differentiable.
OpenStudy (anonymous):
gotcha!