Question

Can anyone help me figure out how the heck they got this answer? Its science
Coulombs Law:
F = Kq1 q 2
d = distance between the charged particles
q1 = quantity of charge of 1 particle
q2 = quantity of charge of the other particle
K = Constant equal to 9.0*10^9 N-m^2 / C^2

The problem and the answer they got for it will be in a comment. PLEASE HELP!!!! (:

Answer 1

A hydrogen atom has one proton in its nucleus, which is surrounded by just one electron. The average distance between a proton and an electron in a hydrogen atom is 5.3 * 10^-11 m. What is the electrical force between a proton and an electron in a hydrogen atom?

They said that this would be the answer:

F = (9.0 * 10^9 N-m^2 / C^2) * [(1.6 * 10^-19 C) (1.6 * 10^-19 C)] / (5.3 * 10^-11 m ^2)
F = 8.2 * 10^-8 N

Answer 2

OH DAMN

Answer 3

IKR!! >.<

Answer 4

heeeeeeeeeeelp? ANybody?

Answer 5

What chu tryin to find.

Answer 6

it looks really confusing.

Answer 7

I'm trying to find the electrical fouce between a proton and an electron in a hydrogen adom >.<
So many people viewing... yet so little helping :(

Answer 8

atom*

Answer 9

Like..the distance?

Answer 10

force*

Answer 11

No like the force

Answer 12

HOlD ON.

Answer 13

is it a worksheet?

Answer 14

q1 * q2
F = k--------
r^2


this is the correct formula

Answer 15

Easy
F=kqq/r^2
So
\[F=proton charge*electroncharge/(distance^2)\]

Answer 16

oops
*k

Answer 17

IK! But did you take a look at the work they said is CORRECT? The answer they gave me? the piece where they showed there work?

Answer 18

Ivy is it a worksheet????

Answer 19

Ivy is it a worksheet????

Answer 20

k=9*10^-9
proton charge=1.6*10^-19
electron charge=1.6*10^-19
and the distance between them is=5.3*10^-11
The worksheet is correct, and their answer is correct
just follow their work

Answer 21

Your just repeating the information i already knew...
I was ASKING for you to show the steps please.
And nope its a lesson for online schooling >.<

Answer 22

The information is plug and chug. The electrical force is F=kqq/r^2, like in the given information. You just have to find F by plugging in all the known information. There's only one step here.

Answer 23

IK!
But like... i tried doing the math like i plugged everything in like they said.
Being the first step is to
[(1.6 * 10^-19 C) (1.6 * 10^-19 C)]
Which I am pretty sure is
2.56 * 100^361 C ?.....
Then you have to multiply
(9.0 * 10^9 N-m^2 / C^2) *
giving what i think is
23.04 * 1000^3249
Then you divide?
IDK :P

Answer 24

ivy, i do online schooling aswell.. whats the programs name of your online schooling.?

Answer 25

@creepy
after calculation found yr ans correct ....

Answer 26

wait nonono
when you multiply, you don't multiply the exponents, you add them.
So \[(1.6 * 10^-19 C) (1.6 * 10^-19 C)=2.56*10^-38\]

Answer 27

C^2

Answer 28

@creepy
YR ANS IS CORRECT ...

Answer 29

@ Hark
After calculation i found it to NOT be the answer they gave me ^ i wrote it above
This is a lesson not an assignment ^.^

Answer 30

Wait so PJW, you dont multiply the 10s together? ;o

Answer 31

nope when you multiply 10 to the power of somethings together, you add the exponents. So 10^-19*10^-19=10^-38

Answer 32

DO YOU WANT ME TO GIVE YOU THE SOLUTION OR WHAT ??????

Answer 33

Ah, i seeeeeeee
So then you get
(2.56 * 10^-38) * (9.0 * 10^9 N-m^2 / C^2)
?
Which would be..
23.04 * 10^-27 N-m^2 / C^2
?

Answer 34

What do you mean Hark? I already have the solution i just need to know how to get it SPECIFICALLY.
Like PJW is showing me

Answer 35

Well
I am off to eat and cool off.
Hope you answered my question when i get back >:(
Bbl

Answer 36

okay here it is q1 x q2 = \[(1.6 x 10^{-19})(1.6x10^{-19}) = 2.56 x 10^{-38}\]

Answer 37

k*q1*q2 = \[(9.0 x 10^{9})(2.56 x 10^{-38}) = 23.04 x 10^{-29}\]

Answer 38

d (or r) = \[5.3 x 10^{-11}\]

Answer 39

alright, keep going.. (:

Answer 40

so \[d ^{2} = (5.3 x 10^{-11})(5.3 x 10^{-11}) = 28.09 x 10^{-22}\]

Answer 41

so finally
k q1q2
F = ---------
d^2

\[23.04 x 10^{-29}\]---------------------- \[28.09 x 10^{-22}\]

Answer 42

Wow!
Thats a lot more work than i thought.. keep goin
It says i have to get
F = 8.2 * 10^-8 N

Answer 43

this gives \[0.82 x 10^{-29 +22}\]
which gives \[0.82 x 10^{-7}\]

Now you hv to put it in scientific notation that is move the decimal to the right by one place
To achieve this we multiply it by 1 in the form 10/10
the 10 in the numerator multiplies 0.82 to give 8.2 and the 10 in the denominator goes up as 10^-1
so we finally get \[8.2 x 10^{-8}\]

Answer 44

I hope this is clear now. You have to use the laws of exponents here

\[a ^{m} x a ^{n} = a ^{m+n}\]
and
\[a ^{m}/a ^{n} = a ^{m-n}\]

Answer 45

Hey creepy...

Is it clear now?????

Answer 46

Oh!
Yea its pretty clear now (:
Thanks so fricking much ;D