Question

derive the value of whole root of1+sinx/1_sinx

Answer 1

if you want the value, then you must supply a value for x

Answer 2

simplification needed

Answer 3

multiply top and bottom by conjugate

Answer 4

it will simplify to something like sinx

Answer 5

dammit that is right. I didn't think of that!

Answer 6

or similar

Answer 7

what do you mean by root?
like a square root or find the zero

Answer 8

\[\sqrt{\frac{1+\sin(x)}{1-\sin(x)}}\]

Answer 9

first ignore the sqrt

Answer 10

\[\frac{1+\sin(x)}{1-\sin(x)} \times \frac{1+\sin(x)}{1+\sin(x)} \]

Answer 11

ahh ok then

Answer 12

wait

Answer 13

should multiply by 1-sinx

Answer 14

but its same idea

Answer 15

(1+sinx)/cosx

Answer 16

or secx + tanx

Answer 17

you will get some 1-sin^2 , which can be changed to cos^2 , then the sqrt disappears when you include the sqrt

Answer 18

no elecengineer you were right first time, conjugate is 1+sinx

Answer 19

nah but i remember certain times you dont multiply by the conjugate of the bottom, when you evaluate certain limits you dont , it all depends on whether you want the diff of squares on the top or bottom

Answer 20

ah dont worry