derive the value of whole root of1+sinx/1_sinx

Question

anonymous · Answer

if you want the value, then you must supply a value for x

anonymous · Answer

simplification needed

anonymous · Answer

multiply top and bottom by conjugate

anonymous · Answer

it will simplify to something like sinx

anonymous · Answer

dammit that is right. I didn't think of that!

anonymous · Answer

or similar

dumbcow · Answer

what do you mean by root?
like a square root or find the zero

anonymous · Answer

$$\sqrt{\frac{1+\sin(x)}{1-\sin(x)}}$$

anonymous · Answer

first ignore the sqrt

anonymous · Answer

$$\frac{1+\sin(x)}{1-\sin(x)} \times \frac{1+\sin(x)}{1+\sin(x)} $$

dumbcow · Answer

ahh ok then

anonymous · Answer

wait

anonymous · Answer

should multiply by 1-sinx

anonymous · Answer

but its same idea

dumbcow · Answer

(1+sinx)/cosx

dumbcow · Answer

or secx + tanx

anonymous · Answer

you will get some 1-sin^2 , which can be changed to cos^2 , then the sqrt disappears when you include the sqrt

dumbcow · Answer

no elecengineer you were right first time, conjugate is 1+sinx

anonymous · Answer

nah but i remember certain times you dont multiply by the conjugate of the bottom, when you evaluate certain limits you dont , it all depends on whether you want the diff of squares on the top or bottom

anonymous · Answer

ah dont worry