Question

how do i find the zeros of x^4-5x^3+8x^2-10x+12 ? i already found x=2, but im not sure how to find the rest bc i used synth. division but didnt find any more real zeros and i cant remember how to find imaginary zeros. help!

Answer 1

ok after factoring out the (x-2) you get
x^3-3x^2+2x-6
factor this by grouping
x^2(x-3) + 2(x-3)
(x^2+2)(x-3)
x-3=0 --> x=3
x^2+2 =0
x^2=-2
x=+-sqrt(-2)
x = +-sqrt(2)i

Answer 2

thank you!!!

Answer 3

your welcome :)