Question

Write the slope-intercept equation for the line that passes through (-7, 6) and is perpendicular to -7x + 9y = -2

Answer 1

hi you can change the equation to the form y=mx+b and your slope is m, b intercept

Answer 2

-7x + 9y = -2
9y = -2 + 7x or write it as
9y= 7x-2

7x - 2
y= ---- ---
9 9

here your slope m= 7/9 right?


but you prob wants a perpendicular to your line y=(7/9)x-(2/9)
in order to be perpendicular ti this line your m2= -1/m1

Answer 3

ok

Answer 4

so we get m2= -1/m1
m2= -1/(7/9)
m2= -9/7
now that we know its slope we can form an equation of that line perpendicular to the first one

Answer 5

okay am following your lead

Answer 6

using the formula
m=(y2-y1)/(x2-x1) or we can arrange them to
y2-y1= m ( x2 - x1) just plug in your points(-7,6)=(x1,y1) here x1=-7 and y1=6
y2-6 =(-9/7)[x2-(-7)] now just change y2=y and x2=x
y - 6 =(-9/7)[ x -(-7)]
y - 6 =(-9/7)( x + 7 ) now do multiplication and subtraction
y-6= -(9/7)x + (-9/7)7
y-6= -(9/7)x - 7
y = -(9/7)x - 7+6
y = -(9/7)x - 1 ans equation of the line perpendicular to the first line equation

Answer 7

let me hear from you that you got it or not..lol

Answer 8

sry i was checking another problem

Answer 9

well i am looking at it and my mind is playing catch up