Question

The intensity I (measured in watts/m2) of a sound system at a rock concert is measured at 1 watt/m2
on the first
night. If it is measured at
1
100 watt/m2
on the second night, what difference will it make to the intensity level β
(measured in decibels)?

Answer 1

Becomes twice

Answer 2

Is that second measurement 1/100 or 100? The 1 above the 100 is confusing.

Answer 3

assuming 100 watt per square meter, the second night shows an increase in watts per square meter of 100 times what you measured the first night.

dB = 10 log p(2)/p(1)
dB = 10 log 100/1
dB = 10 log 100
dB= 10 X 2= 20 dB or a 20 db increase on the second night

Answer 4

It's 1/100

Answer 5

Then it would be 20 dB down.

Answer 6

Thank you:)