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Mathematics 16 Online
OpenStudy (anonymous):

I need to find the derivative for f(x) = e^x/((e^x+3)(x+3)) and have no idea how to proceed. Everything I have tried has not come out right. How would I approach this problem?

OpenStudy (amistre64):

f(x) = e^x ---------- ; its justsa matter of keeping track of the derivative (e^x+3)(x+3) rules right?

OpenStudy (amistre64):

go ahead and exapnd the bottom to make life easier

OpenStudy (anonymous):

\[f'(x)={e^x(e^x+3)(x+3)-e^x[(e^x+3)+e^x(x+3)] \over (e^x+3)^2(x+3)^2}\]. You need to work in the simpilification a little bit.

OpenStudy (anonymous):

on*

OpenStudy (anonymous):

Anwar, can you show me the steps between so I can understand how you got to that answer? It's correct, but I have no idea how you got to it.

OpenStudy (anonymous):

Well, actually there is no steps in between. It's just one step using both quotient and product rules. Let's say that the top is \(g(x)\) and the bottom is \(h(x)\), then we have this formula: \[f'(x)=({g(x) \over h(x)})'={h(x)g'(x)-g(x)h'(x) \over (h(x))^2}\] It's better to find \(h'(x)\) first using the product rule and then substitute in \(f'(x)\), that would make it easier and would help you to avoid making any mistakes.

OpenStudy (anonymous):

Thank you. I understand it now. Looks like I was on the right track but just didn't go far enough.

OpenStudy (anonymous):

Good :)

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