Question

Some help please???

Answer 1

0.2^(x-1)<=5*0.04^(x-1)

Answer 2

and solve for x i assume?

Answer 3

Apply logarithm

Answer 4

yes....
if i used log wouldn't x be depended by log5? and the answer must be only an interval

Answer 5

or half interval or not***

Answer 6

\[0.2^{x-1}\ \ge\ 5*0.04^{x-1}\]

(x-1) log(.2) >= log(5) + log(.04) (x-1)

Answer 7

log(.04) (x-1)=log0.04^(2x-2)
but wht abt log5???

Answer 8

log(a*b) = log(a) + log(b)

log(5* .04^(...)) = log(5) + log(.....)

Answer 9

=log0.2^2x-2*************

Answer 10

yea i know those thnx...but the answer shouldn't include any log5....

Answer 11

(x-1) log(.2) - (x-1) log(.04) >= log(5)

(x-1) (log(.2) - log(.04)) >= log(5)

x-1 >= log(5)/[log(.2/.04)]

x >= 1 + \(\frac{log(5)}{log(20/4)}\)

Answer 12

x >= 1 + log(5)/log(5)

x >= 2

Answer 13

you say you know these things; do you then choose to not apply them? :)

Answer 14

and it looks like i flipped the inequality by accident

Answer 15

I DO KNOW THESE!!!!!!!! Is just that.....idk.....my brain is on vacations in Hawaii and it hasn't come back yet so.....:P:P :(:(:(:(:(
Thanks ^_^ :)