Question

satellite73 can you help me 54) please!
http://imageshack.us/photo/my-images/832/page533.jpg/

Answer 1

didn't we do this one?

Answer 2

\[55=1200(\log_{2}225)\]?

Answer 3

you du 53

Answer 4

oh second part hold one let me look

Answer 5

solve
\[55=1200\log_2(\frac{225}{x})\] for x yes?

Answer 6

yes slove x

Answer 7

step 1 divide both sides by 1200

Answer 8

\[\frac{55}{1200}=\frac{11}{240}=log_2(\frac{225}{x})\]

Answer 9

step 2 use the property of log that says
\[\log(\frac{b}{a})=\log(b)-\log(a)\]

Answer 10

\[\frac{11}{240}=\log_2(225)-\log_2(x)\]

Answer 11

step 3 get
\[log_2(x)\] by itself on one side of the equal sign
\[\log_2(x)=\log_2(225)-\frac{11}{240}\]

Answer 12

step 4 figure out what the heck that number is on the right hand side. use a caclulator

Answer 13

of course you do not have
\[\log_2\] on your calculator so you use
\[\log_2(255)=\frac{\log(255)}{\log(2)}\]

Answer 14

where the log is the one on your calculator. i get something close to 8. then add 11/240 to get 8.04 rounded

Answer 15

so now we have
\[\log_2(x)=8.04\] and rewrite in equivalent exponential form to get
\[x=2^{8.04}=263\]

Answer 16

and that is your answer.

Answer 17

hope the steps are more or less clear. i wrote what i did for each one

Answer 18

8-11/240=8

Answer 19

oh damn i added when i should have subtracted. good eye sorry

Answer 20

should be 247

Answer 21

\[\frac{\log(255)}{\log(2)}-\frac{11}{240}=7.949\] rounded giving
\[\log_2(x)=7.949\]
\[2^{7.949}=247\]

Answer 22

ty

Answer 23

yw