evaluate the limit as x goes to 0:
6x/tan(8x)?

Question

amistre64 · Answer

lhopital it; and see what you get

amistre64 · Answer

6/8sec^2(8x)

anonymous · Answer

thanks, no t allowed to use lhopital :-)

amistre64 · Answer

(6/8) cos^2(0) = 3/4

anonymous · Answer

yay! that's what I got!!!

amistre64 · Answer

not allowed to use ?? lol.  the answer doesnt really care how its found

anonymous · Answer

haha, I hear you> I asked my teacher abt L'hopital and she was very adamant taht I show calc's the way she is teaching us :-(

amistre64 · Answer

i want you to move 3 feet to your left; but in order to get there, you have to run around the block first ...lol

amistre64 · Answer

the other way i spose is just throw in the f(x+h)-f(x)/h  conflageration

anonymous · Answer

I completely agree with you!

anonymous · Answer

we have to sub sin and cos and then use the rules

myininaya · Answer

$$\frac{6x}{\frac{\sin(8x)}{\cos(8x)}}=6x*\frac{\cos(8x)}{\sin(8x)}=6x*\cos(8x)*\frac{1}{\sin(8x)}$$
=$$6*\cos(8x)*\frac{8x}{\sin(8x)}*\frac{1}{8}$$

anonymous · Answer

just put another one up

myininaya · Answer

x->0, cos(8x)->1
x->0, 8x/sin(8x)->1
so we have 6*1/8=6/8=3/4

anonymous · Answer

thanks Myin, I got it though