can some one pls explain this to me: The limit as h goes to 0: ((sqrt(3+h)-sqrt(3)))/h represents the derivative of a function f at a number c. Determine f and c. Thank you!
sqrt(x) derives to 1/2sqrt(x)
\[\frac{\sqrt{x+h}-\sqrt{x}}{h}=\frac{\sqrt{x+h}}{h}-\frac{\sqrt{x}}{h}\] cant recall it really
maybe it the \[\frac{f(b)-f(a)}{b-a}\]version
ueah; i think its has to do with the conjugate
\[\frac{\sqrt{x+h}-\sqrt{x}}{h}*\frac{\sqrt{x+h}+\sqrt{x}}{\sqrt{x+h}+\sqrt{x}}\]
tryig to type and math at the same time... messed it up lol
haha - no worries< Im going through it all
what does the q mean when it asks for f and c? that;s my real issue
that 2sqrt(garbage) up top is not spose to even be there; when you multiply conjugates there is no middle term :)
q?
question \
oh; its asking for the derivative of the function and the value used which is 3 n this case
I calc'ed it hoping that;s what it meant :-)
what do you mean by value?
\[\frac{h}{h(\sqrt{x+h}+\sqrt{x})}\] \[\lim_{h->0}\ \frac{1}{\sqrt{x+h}+\sqrt{x}}\ =\frac{1}{\sqrt{x}+\sqrt{x}}\]
you see how they begin with 3+h instead of x+h? c = 3
f(c) = \(\frac{1}{2\sqrt{c}}\) when c = 3
yes, i see that
so c is the x value?
yes; c usually denotes the term of the limit as in \(\lim_{x->c}\)
oh, I see!
to determine the f or derivative would I be required to plug in the 0 at the end? since it is h goes to 0?
c = ssqrt3
\[\lim_{x->3}\frac{\sqrt{x+h}-\sqrt{x}}{h}=\frac{1}{2\sqrt{x}}=\frac{1}{2\sqrt{3}}\]
here's the answer
f(x)=sqrtx at the point c = 3
well, yeah; sqrt(x) derives to; 1/2sqrt(x)
i try to do those mathlab type websites where they give you practice problems ...... i loathe them. they never seem to be able to say exactly what it is they want you to do lol
that was my issue with this question....
Thanks for your help!
:) just swear at the computer monitor and click next :)
so to calc f I am saying as x goes to 3
hahahaha! I wish I could. I am changing careers and they wont take my highschool calc classes ( over a decade ago) so im back in calc and have to do well
the question asked, in hindsight, what function are they deriving and what did they use for 'c' f(x) = sqrt(x) and c = 3
thanks!
that was a really backwards way to ask such an easy question?
thanks a ton amistre! you are awesome! off to sleep, have to wake up early to trade oil :-)
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