Question

Need the steps please.
(3y+12)/(8y^3 ) ÷ (9y+36)/(16y^3 )

Answer 1

the first thing to do is:
change that division for a multiplication. You can do that by changing the numerator by the denominator of the right side of the equation. That is:
(3y+12)/(8y^3 ) X (16y^3 )/ (9y+36)
Now you have to multiply numerators and denominators each other.
(3y+12)(16y^3 )/(8y^3 )(9y+36)

Answer 2

Read this while I edit the remain

Answer 3

ok

Answer 4

2/3

Answer 5

need the steps.

Answer 6

If you can see, there are common factors both in the numerator and denominator. So the expression becomes....
3(y+4)(16y^3 ) / 9 (8y^3 )(y+4)
(y+4) in the numerator and denominator simplify
3(16y^3 ) / 9 (8y^3 )
You can also simplify 3 in the numerator with 9 in the denominator
(16y^3 ) / 3 (8y^3 )
Then you can finally simplify 16 in the numerator and 8 in the denominator
(2y^3 ) / 3 (y^3 )
Division y^3/y^3 is equal to 1, so
Everything has been simplified to 2/3

Answer 7

thanks a lot.

Answer 8

your welcome

Answer 9

Thanks for the medal

Answer 10

welcome u deserve it.