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OpenStudy (anonymous):
x = 0 or 3
OpenStudy (anonymous):
x=0 or x=81 (no3)... :)
OpenStudy (anonymous):
x^2=3^4 * x
x(x-81)=0
x=0 or x=81
OpenStudy (anonymous):
inik is correct, x = 0 or 81
OpenStudy (anonymous):
3 squared which is then has the square root taken twice is the same as square root of 3
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OpenStudy (anonymous):
(9)^1/4=(3)^1/2
OpenStudy (anonymous):
i got lost on this x^2=3^4 *?? how did u get that?
OpenStudy (anonymous):
ok 9 can be expressed as (3)^2, correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
(x)^1/2=(3x)^1/4 (your question), take each side of the equal sign and do this ((x)^1/2)^4 = ((3x)^1/4)^4
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OpenStudy (anonymous):
which then becomes (x)^2=3x, (x)^2 - 3x=0. Factor out an x which gives you, x(x-3)=0
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
plug it in to a calculator and see, but im pretty sure im in the ball park
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
=D
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OpenStudy (anonymous):
thank u
OpenStudy (anonymous):
no problem, what math class are you in?
OpenStudy (anonymous):
college algebra
OpenStudy (anonymous):
ah, are you allowed to use a calculator?
OpenStudy (anonymous):
if you aren't, id suggest looking at numbers that you see raised to a power like 4^2=16, so that square roots and other crazy radicals can be seen easy like ((3)^1/7)^2)= 3^2/7
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